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Q.

A body of mass 2kg is moving along positive X-direction with a velocity of 5 ms–1. Now a force of 102 N is applied at an angle 450 with X-axis. Its velocity after 3s is

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a

25 ms−1

b

20 ms−1

c

15 ms−1

d

5 ms−1

answer is C.

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Detailed Solution

The force acting is given by F=10i^+10j^⇒a=5i^+5j^

So after 5sec vx=5+5(3)=20ms-1, vy=0+5(3)=15ms-1

So, the magnitude of the final velocity is 25ms-1

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