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Q.

A body of mass 2kg is moving along positive X – direction with a velocity of $5 m s^{- 1}$ . Now a force of $10 \sqrt{2}$ N is applied at an angle $45^{0}$ with X – axis. Its velocity after 3s is,

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a

$20 m s^{- 1}$

b

$15 m s^{- 1}$

c

$25 m s^{- 1}$

d

$5 m s^{- 1}$

answer is C.

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Detailed Solution

Question Image

$F_{x} = 10 \sqrt{2} \cos 45^{0} = 10 N$

$F_{y} = 10 \sqrt{2} \sin 45 = 10 N$

$V_{x} = u_{x} + a_{x} t = 5 + \frac{10}{2} \times 3 = 20 m s^{- 1} V_{y} = u_{y} + a_{y} t = 0 + \frac{10}{2} \times 3 = 15 m s^{- 1}$

$V = \sqrt{V_{x}^{2} + V_{y}^{2}} = \sqrt{20^{2} + 15^{2}}$

$= 25 m s^{- 1}$

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