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A body of mass 2kg is placed on a rough horizontal surface . Coefficient of friction between the surfaces is 0.75.The minimum force required to start sliding the body is (g=10 ms^-2)

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20 N

12 N

15 N

10 N

answer is A.

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Detailed Solution

$F_{\min} = W \sin ϕ = \frac{μ m g}{\sqrt{μ^{2} + 1}}$

$= \frac{(\frac{3}{4}) \times 20}{\sqrt{{(\frac{3}{4})}^{2} + 1}} = \frac{3 \times 20}{5} = 12 N$

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