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A body of mass 2kg is projected at 60⁰ with horizontal on level ground.At a point in its path its velocity is 5 ms^-1 and makes 37⁰ with horizontal. The kinetic energy of projection of the body is (sin 37⁰ = 0.6)

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4 J

1 J

128 J

64 J

answer is C.

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Detailed Solution

$u \cos θ = V \cos \propto \Rightarrow u = \frac{5 \times \frac{4}{5}}{\frac{1}{2}} = 8 {ms}^{- 1}$

$K E = \frac{1}{2} \times 2 \times 8^{2} J = 64 J$

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