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Q.

A body of mass 2kg is thrown up vertically with kinetic energy of 490J. If g = 9.8/ms2 , the height at which the kinetic energy of the body becomes half of the original value, is

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a

50m

b

25m

c

12.5m

d

19.6m

answer is C.

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Detailed Solution

At projection, T.E= K.E = 490 

at given point, P.E'+K.E'=T.E

⇒mgh+K.E2=T.E

⇒h=2×T.E. - K.E.2mg=4902×2×9.8=12.5 m

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