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Q.

A body of mass 2kg lying on ice which given a velocity of 6 ms−1 is stopped by friction is 5sec find the co-efficient of friction between block and ice (g=10 ms−2)

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a

0.25

b

0.18

c

0.34

d

0.12

answer is A.

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Detailed Solution

fk=f

μkmg=ma

μk=ag

v=u+at

0=6+a(5)

a=−65m/s2

65=μ×10

μ=650=0.12

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