A body of mass 2kg travels according to the law x(t) = pt + qt2 + rt3 where p = 3ms-1 , q = 4ms-2 and r = 5ms-3. The force acting on the body at t = 2 seconds is :

F=dpdt=mdvdt=md2xdt2=2[2q+6rt]=136N

F=dpdt=mdvdt=md2xdt2=2[2q+6rt]=136N

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A body of mass 2kg travels according to the law x(t) = pt + qt² + rt³ where p = 3ms^-1 , q = 4ms^-2 and r = 5ms^-3. The force acting on the body at t = 2 seconds is :

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134 N

68 N

158 N

136 N

answer is A.

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$F = \frac{dp}{dt} = m \frac{dv}{dt} = m \frac{d^{2} x}{{dt}^{2}} = 2 [2 q + 6 rt] = 136 N$

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