A body of mass $300 g$ kept at rest breaks into two parts due to internal forces. One part of mass $200 g$ is found to move at a speed of $12 m / s$ towards the east. The velocity of the other part is_

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12 m / s

towards the east.

16 m / s

towards the east.

18 m / s

towards the west.

24 m / s

towards the west.

answer is D.

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Detailed Solution

A body of mass

300 g

kept at rest breaks into two parts due to internal forces. One part of mass

200 g

is found to move at a speed of

12 m / s

towards the east. The velocity of the other part is

24 m / s

towards the west.
According to the given information,
Initial velocity is zero because, initially, the body was at rest.
So, initial linear momentum of the body is thus

p_{1} = mu = 0

.
Now since the body breaks due to internal forces. However, the external force acting on it is zero. Its linear momentum will remain constant, that is, zero.

p_{1} = m_{1} v_{1}

= 200 \times 12

(towards the east)
Again, the linear momentum of the other part must have the same magnitude and should be opposite in direction. It, therefore, moves towards the west. If its speed is