Q.

A body of mass 40 kg stands on a weighing machine in an accelerated lift. The reading on the scale of the weighing machine is 300 N. Find the magnitude and direction of acceleration. (g=9.8ms2)

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a

2.3m/s2downward

b

4.6m/s2upward

c

4.6m/s2down ward

d

2.3m/s2upward

answer is B.

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Detailed Solution

m=40kg,w=300N

w=m(ga)  (lift moving down ward)

300=40(ga)

30040=ga

a=9.8304

=39.2304

=9.24

=2.3m/s2downward  

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A body of mass 40 kg stands on a weighing machine in an accelerated lift. The reading on the scale of the weighing machine is 300 N. Find the magnitude and direction of acceleration. (g=9.8 ms−2)