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Q.

A body of mass 40 kg stands on a weighing machine in an accelerated lift. The reading on the scale of the weighing machine is 300 N. Find the magnitude and direction of acceleration. (g=9.8 ms−2)

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a

2.3 m/s2 downward

b

4.6 m/s2 upward

c

4.6 m/s2 down ward

d

2.3 m/s2 upward

answer is B.

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Detailed Solution

m=40kg, w=300N

w=m(g−a)  (lift moving down ward)

300=40(g−a)

30040=g−a

a=9.8−304

=39.2−304

=9.24

=2.3 m/s2 downward  

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