A body of mass 5 kg is placed at the origin, and can move only on the x-axis. A force of 10 N is acting on it in a direction making an angle of $60°$ 60 ⁰with the x – axis and displaces it along the x - axis by 4 metres. The work done by the force is

To calculate the work done by a force applied at an angle to the direction of displacement, we use the formula:

Work (W) = Force (F) × Displacement (d) × cos(θ)

In this scenario:

Force (F): 10 N

Displacement (d): 4 meters

Angle (θ): 60°

First, calculate the cosine of the angle:

• cos(60°) = 0.5

Now, apply the values to the work formula:

• W = 10 N × 4 m × 0.5
• W = 20 Joules

Therefore, the work done by the force is 20 Joules.

The correct option is d) 20 J.

This calculation aligns with the principles of work and energy in physics, where only the component of the force parallel to the displacement contributes to the work done.