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A body of mass $500 g$ is resting on a frictionless table. The force of $0.01 N$ acted upon by an acceleration of the body. Which of the following is the acceleration of the body?

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0.02 m / s^{2}

0.5 m / s^{2}

0 . 75 m / s^{2}

0.12 m / s^{2}

answer is A.

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Detailed Solution

A body of mass

500 g

is resting on a frictionless table. The force of

0.01 N

acted upon by an acceleration of the body. The acceleration of the body is

0.02 m / s^{2}

.
Given that,
A body of mass

= 500 g

Force applied

= 0.01 N

Acceleration can be calculated from the relation of the

F = ma

Putting all the values in the equation

0.01 = \frac{500}{1000} \times a

= > a = \frac{0.01}{0.5}

On solving the equation

a = 0.02 m / s^{2}

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