A body of mass 50g at 1000 C is dropped into 100g of water at 200 C contained in a copper calorimeter of mass 50g. The final temperature attained is 300 C. The specific heat of material of body is x700 calg0C. The value of x is: (Specific heat of copper is 0.09 cal / g0 C) ?

50×cp×(100−30)=50×0.09×(30−20)+100×1×30−20 ⇒3500 cp = 45 + 1000=1045 ⇒cp=10453500=209700

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A body of mass 50g at 100⁰ C is dropped into 100g of water at 20⁰ C contained in a copper calorimeter of mass 50g. The final temperature attained is 30⁰ C. The specific heat of material of body is $\frac{x}{700} \frac{c a l}{g^{0} C}$ . The value of x is: (Specific heat of copper is 0.09 cal / g⁰ C) ?

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answer is 209.

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Detailed Solution

$50 \times c_{p} \times (100 - 30) = 50 \times 0.09 \times (30 - 20) + 100 \times 1 \times (30 - 20) \Rightarrow 3500 c_{p} = 45 + 1000 = 1045 \Rightarrow c_{p} = \frac{1045}{3500} = \frac{209}{700}$

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