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A body of mass 5kg is kept on a rough horizontal surface and it is under the action of 50N horizontal force. If coefficient of friction in between the surfaces is 1.0, the distance it travels in 3 sec is

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1.5m

0.9m

answer is C.

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Detailed Solution

F – f = ma
F - µmg = ma ⇒ 50 -1 x 5 x 9.8 = 5a
a = 10 - 9.8 = 0.2m/ $s^{2}$

S = \frac{1}{2} a t^{2} = \frac{1}{2} \times 0.2 \times 9

⇒ S = 0.9m

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