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A body of mass 5kg is raised from certain depth. By the time it is raised by 10m, if its velocity is $2 m s^{- 1}$ , work done during this time is,

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960J

500J

980J

20J

answer is D.

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Detailed Solution

$W = P E + K E$

$= 5 \times 9.8 \times 10 + \frac{1}{2} \times 5 {(2)}^{2} = 500 J$

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