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Q.

A body of mass 5kg is under the action of 50N on the horizontal surface. If coefficient of friction in between the surfaces is one, the distance it travels in 3 s is (g = 9.8 m/s2)

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An Intiative by Sri Chaitanya

a

1.5m

b

6m

c

2m

d

0.9m

answer is C.

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Detailed Solution

Net force  =  Mass ×accelerationF−f=maF−μmg=ma⇒50−1×5×9.8=5aa=10−9.8=0.2 S=12at2=12×0.20.1×9⇒S=0.9m

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