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Q.

A body of mass 5kg moving along a straight line is accelerated from 4ms–1 to 8ms–1 with the application of a force of 10N in the same direction. Then,

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a

Time for the change in velocity is 2s

b

All the above

c

Work done by the force is 120J

d

Displacement of the body is 12m

answer is D.

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Detailed Solution

a = F/M = 10/5 = 2 m/s2

v = u+at ⇒ t = 2sec

v2-u2 = 2as ⇒ s = 12m

W = FS = 120 J

 

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