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A body of mass 5kg moving along a straight line is accelerated from 4ms^–1 to 8ms^–1 with the application of a force of 10N in the same direction. Then,

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Work done by the force is 120J

Displacement of the body is 12m

All the above

Time for the change in velocity is 2s

answer is D.

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Detailed Solution

$a = \frac{F}{m} = \frac{10}{5} = 2 m / s^{2}$
v = u + at $\Rightarrow$ t = 2sec
v² - u² = 2as $\Rightarrow$ s = 12m
W = FS = 120J

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