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Q.

A body of mass 60 kg is pushed up with just enough force to start in moving on a rough surface with $μ_{s}$ = 0.5 and $μ_{k}$ = 0.4 and the force continues to act afterwards. What is the acceleration of the body ?

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a

14.7 $m s^{- 2}$

b

1.96 $m s^{- 2}$

c

0.98 $m s^{- 2}$

d

4.9 $m s^{- 2}$

answer is C.

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Detailed Solution

F = Applied force = $f_{s} = μ_{s} m g$
$F_{n e t} = F - f_{k} = μ_{s} m g - μ_{k} m g$
a = ( $μ_{s} - μ_{k}$ )g = (0.5 - 0.4)9.8 = 0.98 $m s^{- 2}$

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A body of mass 60 kg is pushed up with just enough force to start in moving on a rough surface with μs = 0.5 and μk = 0.4 and the force continues to act afterwards. What is the acceleration of the body ?