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A body of mass 6kg travelling with a velocity $10 m/s$ collides head - on and elastically with a body of mass 4kg travelling at a speed $5 m/s$ in opposite direction. The velocity of the second body after the collision is

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0 m/s

13 {ms}^{- 1}

6 m/s

8 m/s

answer is D.

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Detailed Solution

m_{1} = 6 kg, m_{2} = 4 kg

$u_{1} = 10 m/s, u_{2} = - 5 m/s$

$v_{2} = \frac{(m_{2} - m_{1}) u_{2}}{(m_{1} + m_{2})} + \frac{2 m_{1} u_{1}}{(m_{1} + m_{2})}$

$= \frac{- 2 \times - 5}{10} + \frac{2 \times 6 \times 10}{10}$

$= \frac{120 + 10}{10}$

$v_{2} = 13 m/s$

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