A body of mass 6kg is under a force which causes displacement in it which is given by s =$\frac{t^2}{4}$ m  , where 't' is time. The work done by the force in 2s is

Complete Solution:

The displacement equation is given by:

s = t²/4

To find velocity (v), differentiate the displacement with respect to time (t):

v = ds/dt = t/2

To find acceleration (a), differentiate the velocity with respect to time (t):

a = dv/dt = 1/2 m/s²

Using Newton’s second law (F = ma):

F = 6 × 1/2 = 3 N

s = t²/4 = 2²/4 = 1 m

Work done (W) is given by:

W = F × s = 3 × 1 = 3 J

Final Answer:

The work done by the force in 2 seconds is 3 J.