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Q.

A body of mass m=0.1kg has an initial velocity of 3i^ms1. It collides elastically with another body B of same mass which has an initial velocity of 5j^ms1. After the collision A moves with a velocity v=4(i^+j^)m/s. The energy of B after the collision is written as x10J. The value of x is.

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Detailed Solution

LCLM 0.1×3i¯+0.1×5j¯=0.1×4(i¯+j¯)+0.1×V¯

V¯=i¯+j¯

KB=12mv2=12(0.1)(2)2=0.1=110J

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