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Q.

A body of mass m is placed on the earth surface is taken to a height of h = 3R, then, change in gravitational potential energy is

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a

$\frac{mgR}{4}$

b

$\frac{2 mgR}{3}$

c

$\frac{3 mgR}{4}$

d

$\frac{mgR}{6}$

answer is C.

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Detailed Solution

$ΔGPE = \frac{mgh}{1 + \frac{h}{R}}$

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