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A body of mass m is projected horizontally with a velocity v from the top of a tower of height h and it reaches the ground at a distance x from the foot of the tower. If a second body of mass 2 m is projected horizontally from the top of a tower of height 2 h, it reaches the ground at a distance 2x from the foot of the tower. The horizontal velocity of the second body is

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$v / 2$

$\sqrt{2} v$

answer is B.

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Detailed Solution

$x=v \sqrt{\frac{2 h}{g}}, 2 x = v^{'} \sqrt{\frac{2 (2 h)}{g}} Solvetoget v^{'} = \sqrt{2} v$

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