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Q.

A body of mass M moving with velocity v undergoes a head on collision with a body of mass m moving with the same velocity but in opposite direction. If the two body stick together after the collision, the speed of the common body will be

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a

zero

b

$(\frac{M - m}{M + m}) V$

c

$(\frac{M + m}{M - m}) V$

d

v/2

answer is C.

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Detailed Solution

. The total momentum before collision = (M-m)v

Momentum after collision = (M+m) V

where y is the speed on composite body. Applying the law of conservation of momentum, we have

$(M + m) V = (M - m) v V = (\frac{M - m}{M + m}) v$

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