Q.

A body of mass 1kg begins to move under the action of a time dependent force F=(2t i^+3t2 j^) N, where i^ and j^ are unit vectors along x-axis and y-axis respectively. What power will be developed by the force at the time t?

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a

2t3+3t4 W

b

2t3+3t5 W

c

2t2+3t3 W

d

2t2+4t4 W

answer is B.

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Detailed Solution

HereF=2t i^+3t2 j^N, m=1 kg a=Fm=2t i^+3t2 j^ N1 kg=2t i^+3t2 j^ ms-2

 Velocity of the body at time t is given by:

v=adt=2t i^+3t2 j^dt=t2 i^+t3 j^   ms-1

 Power developed by the force at time t,

P=F·v=2ti^+3t2j^·t2i^+t3j^ W=2t3+3t5 W

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