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Q.

A body of mass $200 g$ requires $252 J f o r 10^{0} C$ rise of temperature, its thermal capacity is

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a

$126 J K^{- 1}$

b

$0.126 J K^{- 1}$

c

$25.2 J K^{- 1}$

d

$504 J K^{- 1}$

answer is D.

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Detailed Solution

$m = 200 g = 200 \times 10^{- 3} k g Q = 252 J, ∆ t = 10^{0} C, H = ? T h e r m a l c a p a c i t y = \frac{Q}{t} = \frac{252}{10} = 25.2 J K^{- 1}$

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