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Q.

A body of mass m hangs at one end of a string of length l, the other end of which is fixed. It is given a horizontal velocity, so that the string would just reach, where it makes an angle of 60° with the vertical. The tension in the string at bottommost point is

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a

 m g

b

 

 3mg

c

2mg

d

3mg

answer is A.

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Detailed Solution

When body is released from the position P (inclined at angle θ from vertical), then velocity at mean position

v˙=2gl(l-cosθ)

∴ Tension at the lowest point

=mg+mv2l

=mg+ml2gl1-cos60°

=m g+m g=2 m g

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