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Q.

A body of  3kg    moves in XY   plane under the action of force given by  6t i +4t j .   Assuming that the body is at rest at time  t=0,   the velocity of the body at  t=3s   is


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a

12 i +68 j   

b

9 i +6 j  

c

18 i +12 j  

d

18 i +6 j  

answer is A.

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Detailed Solution

Fdt=m(vu)6tdt i ^ +4tdt j ^ =3 v  
2 9 2 i ^ +4 3 2 j ^ = v  
v =9 i ^ +6 j ^  
 
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