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Q.

A body performing simple harmonic with amplitude of 10cm. The velocity of the body is triple by air jet when it is at 5cm from its mean position. The new Aplitude is xcm. The value of x is

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answer is 700.

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Detailed Solution

3V=ωA2x2

V=ω10252.....1

3V=ωA252.....2

3ω10252=ωA252

A2=75×9+25

910025=A225

675+25=700

A=700

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