A body projected up with initial velocity 50 m/s. Distance travelled by the body in last second of its upward motion is (g = 10 m/s²)

We want to find d in the last second of motion, so the time (t) for the last second is 1 second.

Substituting these values into the equation:

$\mathrm{d}=(50\mathrm{m}/\mathrm{s})\left(1\mathrm{s}\right) + \frac{1}{2}(-10 \mathrm{m}/{\mathrm{s}}^2){\left(1\mathrm{s}\right)}^2$

Now, calculate d:

$\mathrm{d}=50\mathrm{m}-5\mathrm{m}=45\mathrm{m}$

So, the distance travelled by the body in the last second of its upward motion is 45 meters.