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A body projected vertically up with a velocity of 58.8 m/s. After 3s if the acceleration due to gravity of earth disappears then the distance travelled and the velocity of the body at the end of next 5 sec is

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$147 m, 29.4 m / s$

$29.4 m, 147 m / s$

$14.7 m, 2.94 m / s$

$19.6 m, 240 m / s$

answer is A.

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Detailed Solution

$v = u - gt$
After 3 seconds it move with constant velocity

v=58.8-3(9.8)=29.4 m/s

distance travelled =5x29.4 =147 m

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