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Q.

A body rolls down an inclined plane  without slipping. The kinetic energy of rotation is 50% of its translational kinetic energy. The body is:

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a

Solid sphere

b

Solid cylinder

c

Hollow cylinder

d

Ring

answer is B.

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Detailed Solution

Translational kinetic energy =12mv2
Rotational kinetic energy =122
According to question
122=12×12mv2 As   v =( pure rolling )122=14mR2ω2I=12mR2
Thus, body should be solid cylinder.

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A body rolls down an inclined plane  without slipping. The kinetic energy of rotation is 50% of its translational kinetic energy. The body is: