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A body slides down a frictionless track which ends in a circular loop of diameter $D$ , then the minimum height $h$ of the body in term of $D$ so that it may just complete the loop, is

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$h = \frac{5 D}{2}$

$h = \frac{D}{4}$

$h = \frac{5 D}{4}$

$h = \frac{3 D}{4}$

answer is B.

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Detailed Solution

$h = \frac{5}{2} R = \frac{5}{2} (\frac{D}{2}) = \frac{5 D}{4}$

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