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Q.

A body, starting from rest and moving with a constant acceleration, covers a distance s₁ in the 4^th second and a distance s₂ in the 6^th second. The ratio $\frac{s_{1}}{s_{2}}$ is:

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a

$\frac{2}{3}$

b

$\frac{6}{11}$

c

$\frac{7}{11}$

d

$\frac{4}{9}$

answer is D.

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Detailed Solution

Distance traveled by the body in nth second is given by:

$s = u + \frac{a}{2} (2 n - 1)$

Since u= 0, we have:

$s_{1} = 0 + \frac{7 a}{2} = \frac{7 a}{2} and s_{2} = 0 + \frac{11 a}{2} = \frac{11 a}{2} Therefore, \frac{s_{1}}{s_{2}} = \frac{7}{11}$

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A body, starting from rest and moving with a constant acceleration, covers a distance s1 in the 4th second and a distance s2 in the 6th second. The ratio s1s2 is: