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Q.

A body starts from rest and travels a distance S with uniform acceleration, then moves uniformly a distance 2S and finally comes to rest after moving further 5S under uniform retardation. Find the ratio of average velocity to maximum velocity

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a

$\frac{7}{4}$

b

$\frac{7}{3}$

c

$\frac{4}{7}$

d

$\frac{3}{7}$

answer is D.

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Detailed Solution

$V_{avg} = (\frac{s + 2s + 5s}{t_{1} + t_{2} + t_{3}}) = \frac{8 s}{(\frac{2s}{V} + \frac{2s}{V} + \frac{10s}{V})} = \frac{8 s \times V}{14 s}$

$\Rightarrow \frac{V_{avg}}{V_{max}} = \frac{4}{7}$

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A body starts from rest and travels a distance S with uniform acceleration, then moves uniformly a distance 2S and finally comes to rest after moving further 5S under uniform retardation. Find the ratio of average velocity to maximum velocity