A body starts from rest and accelerates uniformly up to time t1. It then decelerates uniformly up to time t2. During the time interval, t2−t3, it moves with uniform velocity. Finally, the body retards and comes to rest at time t4. Which of the following velocity−time graphs represents the motion of the body?

The body starts at rest and accelerates uniformly up to time t1. Therefore, the velocity−time graph for the body up to time t1 will be a straight line in upward direction (having positive slope).The body decelerates uniformly from time t1 up to time t2. Therefore, the velocity−time graph will be a straight line, but in downward direction (having negative slope).During time interval t2−t3, the body moves with a uniform velocity. Therefore, the velocity−time graph will be parallel to the time axis.During time interval t3−t4, the body retards and finally comes to rest at time t4. Therefore, the velocity−time graph will be a straight line in downward direction (having negative slope).Only the graph shown in alternative A represents the motion of the body.

A body starts from rest and accelerates uniformly up to time t1. It then decelerates uniformly up to time t2. During the time interval, t2−t3, it moves with uniform velocity. Finally, the body retards and comes to rest at time t4. Which of the following velocity−time graphs represents the motion of the body?

The body starts at rest and accelerates uniformly up to time t1. Therefore, the velocity−time graph for the body up to time t1 will be a straight line in upward direction (having positive slope).The body decelerates uniformly from time t1 up to time t2. Therefore, the velocity−time graph will be a straight line, but in downward direction (having negative slope).During time interval t2−t3, the body moves with a uniform velocity. Therefore, the velocity−time graph will be parallel to the time axis.During time interval t3−t4, the body retards and finally comes to rest at time t4. Therefore, the velocity−time graph will be a straight line in downward direction (having negative slope).Only the graph shown in alternative A represents the motion of the body.

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A body starts from rest and accelerates uniformly up to time t₁. It then decelerates uniformly up to time t₂. During the time interval, t₂−t₃, it moves with uniform velocity. Finally, the body retards and comes to rest at time t₄. Which of the following velocity−time graphs represents the motion of the body?

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Detailed Solution

The body starts at rest and accelerates uniformly up to time t₁. Therefore, the velocity−time graph for the body up to time t₁ will be a straight line in upward direction (having positive slope).

The body decelerates uniformly from time t₁ up to time t₂. Therefore, the velocity−time graph will be a straight line, but in downward direction (having negative slope).

During time interval t₂−t₃, the body moves with a uniform velocity. Therefore, the velocity−time graph will be parallel to the time axis.

During time interval t₃−t₄, the body retards and finally comes to rest at time t₄. Therefore, the velocity−time graph will be a straight line in downward direction (having negative slope).

Only the graph shown in alternative A represents the motion of the body.

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