A body starts from rest and is uniformly accelerated for 30 s. The distance travelled in the first 10 s is x₁, next 10 s is x₂ and the last 10 s is x₃. Then, x₁ : x₂ : x₃ is

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1 : 2 : 4

1 : 2 : 5

1 : 3 : 5

1 : 3 : 9

answer is C.

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Detailed Solution

$\begin{array}{l} x_{1} = \frac{1}{2} a (10)^{2} = 50 a \\ x_{2} = \frac{1}{2} a (20)^{2} - \frac{1}{2} (a) (10)^{2} = 150 a \\ x_{3} = \frac{1}{2} a (30)^{2} - \frac{1}{2} a (20)^{2} = 250 a \\ ∴ x_{1} : x_{2} : x_{3} = 1 : 3 : 5 \end{array}$

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