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Q.

A body starts with a velocity 2i3j+11km/s and moves with an acceleration of 10i+10j+10kms2 . What is its velocity after 0.25 s  

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a

4.5i^+0.5j^13.5k^

b

4.5i^0.5j^13.5k^

c

4.5i^0.5j^+13.5k^

d

4.5i^+0.5j^+13.5k^

answer is C.

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Detailed Solution

v=u+at

=(2i^3j^+11k^)+(10i^+10j^+10k^)0.25

=4.5i^05j^+13.5k^

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