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Q.

A body starts with initial velocity u and moves with uniform acceleration. when the velocity has increased to 5u, the acceleration is reversed in direction, the magnitude remaining constant. Find its velocity when it returns to the starting point?

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a

–u

b

2u

c

–5u

d

–7u

answer is C.

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Detailed Solution

I. By III equation of motion,

v2 = u2+2as

(5v)2 = u2+2as

25v2−u2 = 2as

24u2 = s

2a

∴ Distance travelled : S=12u2​/a

II. v2 = u2+2as

v2 = (5u)2 + 2(−a)(12v2/a​)

v2 = 25v2−24u2

v2 = u2

⇒v = −u.

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