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A body starts with some initial velocity and continues to move along a straight line with constant deceleration. After 3 s it is found to be at a distance of 15 m from the starting point. At 4 s it is at starting point. What is the initial velocity of the body?(Assume constant acceleration.)

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20 ${ms}^{- 1}$

10 ${ms}^{- 1}$

5 ${ms}^{- 1}$

15 ${ms}^{- 1}$

answer is A.

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Detailed Solution

$15 = u \times 3 - \frac{1}{2} a {(3)}^{2}$ ----(1)

$0 = u \times 4 - \frac{1}{2} a {(4)}^{2}$ ----- ( 2)

From (i) and (ii), u = 20 m/s

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