A body takes 5 minutes for cooling from 50∘C to 40∘C. Its temperature comes down to 33.33∘C in next 5 minutes. Now, choose the correct statement(s) from the following ?

50-405 = k50+402-T0and 40-33.335 = k40+33.332-T0on solving above equations, we getT0 = 20∘CAlso 33.33-T5 = k33.33+T2-20 T = 28.88∘C

A body takes 5 minutes for cooling from 50∘C to 40∘C. Its temperature comes down to 33.33∘C in next 5 minutes. Now, choose the correct statement(s) from the following ?

50-405 = k50+402-T0and 40-33.335 = k40+33.332-T0on solving above equations, we getT0 = 20∘CAlso 33.33-T5 = k33.33+T2-20 T = 28.88∘C

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A body takes $5$ minutes for cooling from $50^{\circ} C$ to $40^{\circ} C$ . Its temperature comes down to $33 . 33^{\circ} C$ in next $5$ minutes. Now, choose the correct statement(s) from the following ?

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The temperature of the body in further $5$ minutes becomes $18 . 88^{\circ} C$

The temperature of surrounding is $20^{\circ} C$

The temperature of the body in further $5$ minutes becomes $28 . 88^{\circ} C$

The temperature of surrounding is $25^{\circ} C$

answer is A, D.

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Detailed Solution

$\frac{50 - 40}{5} = k [\begin{matrix} 50 + 40 \\ 2 \end{matrix} - T_{0}]$

and $\frac{40 - 33.33}{5} = k [\begin{matrix} 40 + 33.33 \\ 2 \end{matrix} - T_{0}]$

on solving above equations, we get

$T_{0} = 20^{\circ} C$

Also $\frac{33.33 - T}{5} = k [\begin{matrix} 33.33 + T \\ 2 \end{matrix} - 20] T = 28 . 88^{\circ} C$

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A body takes 5 minutes for cooling from 50∘C to 40∘C. Its temperature comes down to 33.33∘C in next 5 minutes. Now, choose the correct statement(s) from the following ?

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A body takes $5$ minutes for cooling from $50^{\circ} C$ to $40^{\circ} C$ . Its temperature comes down to $33 . 33^{\circ} C$ in next $5$ minutes. Now, choose the correct statement(s) from the following ?