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Q.

A body travels a distance of $(13.8 \pm 0.2) m$ uniformly in a time $(4.0 \pm 0.3) s$ . The velocity of the body in $m s^{- 1}$ is

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a

$(3.45 \pm 0.3)$

b

$(3.45 \pm 0.5)$

c

$(3.45 \pm 0.2)$

answer is B.

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Detailed Solution

$V = \frac{s}{t} = \frac{13.8}{4} = 3.45 m / s$

$\frac{Δ V}{V} = \frac{Δ S}{S} + \frac{Δ t}{t} = \frac{0.2}{13.8} + \frac{0.3}{4} = 0.0895$

$Δ V = V (0.0895) = 3.45 \times 00895 = 0.30$

$V = (3.45 \pm 0.3) m / s$

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A body travels a distance of (13.8±0.2) m uniformly in a time (4.0±0.3) s. The velocity of the body in ms−1 is