A body travels uniformly a distance of $(13.8 \pm 0.2) m$ in a time $(4.0 \pm 0.3)$ s. The velocity of the body within error limits is

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$(3.45 \pm 0.2) m s^{- 1}$

$(3.45 \pm 0.3) m s^{- 1}$

$(3.45 \pm 0.4) m s^{- 1}$

$(3.45 \pm 0.5) m s^{- 1}$

answer is B.

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Detailed Solution

Here, $S = (13.8 \pm 0.2) m$

and $t = (4.0 \pm 0.3) s e c$

Expressing it in percentage error, we have,

$S = 13.8 \pm \frac{0.2}{13.8} \times 100 % = 13.8 \pm 1.4 %$

and $t = 4.0 \pm \frac{0.3}{4} \times 100 % = 4 \pm 7.5 %$

$∵ V = \frac{s}{t} = \frac{13.8 \pm 1.4}{4 \pm 7.5} = (3.45 \pm 0.3) m / s$

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