A body travels uniformly a distance of 30.0±0.2 m and in time 6.0±0.04 s. The velocity of the body is

z=xyΔzz=Δxx+Δyyv=st=30.06.0=5.0 ms-1∆v=∆ssv+v∆tt=∆st+s∆tt2 =0.26.0+30.00.046.02 ≈0.06

A body travels uniformly a distance of 30.0±0.2 m and in time 6.0±0.04 s. The velocity of the body is

z=xyΔzz=Δxx+Δyyv=st=30.06.0=5.0 ms-1∆v=∆ssv+v∆tt=∆st+s∆tt2 =0.26.0+30.00.046.02 ≈0.06

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A body travels uniformly a distance of $(30.0 \pm 0.2) m$ and in time $(6.0 \pm 0.04) s$ . The velocity of the body is

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$(5.0 \pm 0.06) {ms}^{- 1}$

$(5.0 \pm 0.02) {ms}^{- 1}$

$(5.0 \pm 0.1) {ms}^{- 1}$

$(5.0 \pm 0.3) {ms}^{- 1}$

answer is A.

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$\begin{array}{l} z = \frac{x}{y} \\ \frac{Δz}{z} = \frac{Δx}{x} + \frac{Δy}{y} \end{array}$

$v = \frac{s}{t} = \frac{30.0}{6.0} = 5.0 {ms}^{- 1}$

$∆ v = \frac{∆ s}{s} v + v \frac{∆ t}{t} = \frac{∆ s}{t} + s \frac{∆ t}{t^{2}} = \frac{0.2}{6.0} + 30.0 \frac{0.04}{6 . 0^{2}} \approx 0.06$

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A body travels uniformly a distance of 30.0±0.2 m and in time 6.0±0.04 s. The velocity of the body is

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A body travels uniformly a distance of $(30.0 \pm 0.2) m$ and in time $(6.0 \pm 0.04) s$ . The velocity of the body is