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A body weight W, is projected vertically upwards from earth’s surface to reach a height above the earth which is equal to nine times the radius of earth. The weight of the body at that height will be:

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$\frac{W}{100}$

$\frac{W}{3}$

$\frac{W}{91}$

$\frac{W}{9}$

answer is A.

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Detailed Solution

At height $" h "\Rightarrow g_{h} = \frac{{gR}^{2}}{{(R + h)}^{2}}$
$W_{h} = \frac{{WR}^{2}}{{(R + h)}^{2}}$
from surface h = 9R
$W_{h} = \frac{{WR}^{2}}{100 R^{2}} = \frac{W}{100}$

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