A body weight $w$ , is projected vertically upwards from earth’s surface to reach a height  above the earth which is equal to nine times the radius of earth. The weight of the body at  that height will be 

Mass of body , 
 $$\begin{gathered} m=\frac{\text{Weight\hspace{0.17em}\hspace{0.17em}of\hspace{0.17em}\hspace{0.17em}body}}{\text{Acceleration\hspace{0.17em}\hspace{0.17em}due\hspace{0.17em}\hspace{0.17em}to\hspace{0.17em}\hspace{0.17em}gravity\hspace{0.17em}\hspace{0.17em}at\hspace{0.17em}\hspace{0.17em}that\hspace{0.17em}\hspace{0.17em}point}} \\ m=\frac{w}{g} \end{gathered}$$
 
At height h, acceleration due to gravity is given as,  $g_h=\frac{g}{{(1+\frac{h}{R})}^2}$
Here,  $h=9R,g_h=\frac{g}{{(1+\frac{9R}{R})}^2}$
 $=\frac{g}{{(1+9)}^2}=\frac{g}{{\left(10\right)}^2}=\frac{g}{100}$
Weight of body at height of  9R, 
  $w_h=m{g}_h=\left(\frac{w}{g}\right)\times \left(\frac{g}{100}\right) \Rightarrow w_h=\frac{w}{100}$