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A bomb at rest of mass 20 kg explodes in to two fragments whose masses are in the ratio 2:3. The smaller fragment moves with a velocity 6 m/s. Then kinetic energy of larger fragment. is

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Detailed Solution

$\frac{m_{1}}{m_{2}} = \frac{2}{3}, m_{1} + m_{2} = 20$

$m_{1} v_{1} = m_{2} v_{2}$

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