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Q.

A bomb is thrown at a speed  20m/s at an angle  45. At the highest point, it explodes into two parts of equal mass, the one part coming to rest. The distance from the origin to the point where the other part strikes the ground is (in meter)

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answer is 60.

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Detailed Solution

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Range  R=u2gsin2θ=(20)210sin90=40m
The centre of mass will hit the ground at P
 m×R2+mxm+m=R20+x2=40x=60m

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