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A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8 kg mass is 6 m/sec. The kinetic energy of the other mass is

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12 J

288 J

72 J

144 J

answer is D.

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Detailed Solution

$m_{A} v_{A} = m_{B} v_{B} \Rightarrow 4 \times v_{A} = 8 \times 6 \Rightarrow v_{A} = 12 m / s$
\ Kinetic energy of other mass A, $= \frac{1}{2} m_{A} v_{A}^{2}$
$= \frac{1}{2} \times 4 \times (12)^{2} = 288 J$

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