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Q.

A bomber flying upward at an angle of 530 with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g =10ms-2 , the velocity at the time of release of the bomb in ms-1 is 

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a

100

b

400

c

200

d

800

answer is C.

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Detailed Solution

-h=ucosθt-12 gt2

⇒-800=ucos53°×20-12 10202

⇒u=100 m/s

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