A bomber flying upward at an angle of 530 with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g =10ms-2 , the velocity at the time of release of the bomb in ms-1 is

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A bomber flying upward at an angle of 53⁰ with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g =10ms^-2, the velocity at the time of release of the bomb in ms^-1is

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100

400

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800

answer is C.

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Detailed Solution

$- h = u \cos θ t - \frac{1}{2} {gt}^{2}$

$\Rightarrow - 800 = u (c o s 53 °) \times 20 - \frac{1}{2} 10 {(20)}^{2}$

$\Rightarrow u = 100 m / s$

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